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   An All Possible Value Puzzle
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   Author  Topic: An All Possible Value Puzzle  (Read 1756 times)
K Sengupta
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An All Possible Value Puzzle  
« on: Nov 3rd, 2006, 7:05am »
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A, B and C are positive integers.  
Determine all possible values of  C,  for which  the equation:
2^A – 5^B = C , possesses   exactly two distinct solutions.
 
« Last Edit: Nov 3rd, 2006, 7:06am by K Sengupta » IP Logged
ThudnBlunder
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Re: An All Possible Value Puzzle  
« Reply #1 on: Nov 3rd, 2006, 12:07pm »
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Nice problem!
 
So (A1, B1) and (A2, B1) are not distinct?
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Re: An All Possible Value Puzzle  
« Reply #2 on: Nov 3rd, 2006, 3:59pm »
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The question doesn't come up, for if the values of B and C are the same, the values of A must be as well.
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Re: An All Possible Value Puzzle  
« Reply #3 on: Nov 3rd, 2006, 4:27pm »
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on Nov 3rd, 2006, 3:59pm, Icarus wrote:
The question doesn't come up, for if the values of B and C are the same, the values of A must be as well.

I understand now. C is constant (a positive integer) and we need to find what values of this constant allow exactly 2 distinct solutions.    
 
 
 
 
« Last Edit: Nov 3rd, 2006, 4:37pm by ThudnBlunder » IP Logged

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Re: An All Possible Value Puzzle  
« Reply #4 on: Nov 3rd, 2006, 5:59pm »
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One solution (to start with): C = 3.
 
Are there any others?  Undecided
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Re: An All Possible Value Puzzle  
« Reply #5 on: Nov 4th, 2006, 12:27am »
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Hmmm...
 
2x(24r-1) = 5y(52s-1).
 
We'd like to conclude r=s=1.
 
Suppose, for example, that 2|r.  Then 17|24r-1, so 17|52s-1, so 8|s.  Then 11489|52s-1, so 11489|24r-1, so 1436|r.  Etc.?
 
The number 3 might be important.  The number of times 3 divides r is the same as the number of times 3 divides s, for example.  We also know the number of times 5 divides r is y-1, and the number of times 2 divides s is x-3, but I don't know if that helps.
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Re: An All Possible Value Puzzle  
« Reply #6 on: Dec 18th, 2006, 9:14am »
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Actually thanks for T&B's link in another post. I think this riddle just got buried. So this way it will be bumped!!  Cheesy
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Re: An All Possible Value Puzzle  
« Reply #7 on: Dec 18th, 2006, 11:14pm »
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Well, 2x(24r-1) = 5y(52s-1) has only one solution with 0<r,s<106 (much past that I run out of memory cause I'm too lazy to write an efficient program).  But I haven't made any real progress.
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Sameer
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Re: An All Possible Value Puzzle  
« Reply #8 on: Dec 19th, 2006, 10:41am »
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anyway to do this analytically?  Shocked
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Re: An All Possible Value Puzzle  
« Reply #9 on: Jun 23rd, 2007, 8:10pm »
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K Sengupta, did you have a solution?
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K Sengupta
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Re: An All Possible Value Puzzle  
« Reply #10 on: Jun 26th, 2007, 1:49am »
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on Jun 23rd, 2007, 8:10pm, Eigenray wrote:
K Sengupta, did you have a solution?

 
I truly do not have the solution to this one.
 
Prima facie, this problem occurred to my mind having it's unmistakable similarity with the famous 2^x - 3^y = 7 problem which possesses an elementary solution.
 
Having regard to its simplicity, I naively assumed that the 2^x - 5^y case would also lend itself to a similar treatment, a premise which has since proved erroneous.
 
In conclusion, I would like to thank you for your brilliant treatment of the various facets corresponding to the problem under reference, with a hope that someday,  an analytic solution to the foregoing problem could be found.
 
 
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