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   Minimum Triangle Area
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   Author  Topic: Minimum Triangle Area  (Read 639 times)
ThudnBlunder
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Minimum Triangle Area  
« on: Jan 12th, 2004, 3:24pm »
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I came across the following puzzle recently.
It looks difficult to solve without some programming.
 
A triangle with sides a, b, and c has an area A equal to n times its perimeter,  
where a, b, c, n, and A are all positive integers.    
 
Also, a = n2 + n1/5  
 
What is the minimum possible value for A?
 
 
« Last Edit: Jan 30th, 2004, 4:54pm by ThudnBlunder » IP Logged

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Icarus
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Re: Minimum Triangle Area  
« Reply #1 on: Jan 12th, 2004, 4:01pm »
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Is x also restricted to integers?
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ThudnBlunder
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Re: Minimum Triangle Area  
« Reply #2 on: Jan 12th, 2004, 4:24pm »
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Quote:
Is x also restricted to integers?

Iff it is equal to n.   Roll Eyes
 
(Thanks, I will correct that now.)
 
« Last Edit: Feb 2nd, 2004, 5:58pm by ThudnBlunder » IP Logged

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Sameer
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Re: Minimum Triangle Area  
« Reply #3 on: Jan 30th, 2004, 4:00pm »
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on Jan 12th, 2004, 4:01pm, Icarus wrote:
Is x also restricted to integers?

I don't see any x in the questions?  Undecided Huh
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ThudnBlunder
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Re: Minimum Triangle Area  
« Reply #4 on: Jan 30th, 2004, 4:53pm »
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Quote:
I don't see any x in the questions?

So my correction was successful then?  
Thank you for your positive feedback, Sameer.
 Grin
(Before Icarus queried it, I think I originally had Also, a = x2 + x1/5)  
 
 
 
« Last Edit: Jan 30th, 2004, 10:00pm by ThudnBlunder » IP Logged

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Sameer
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Re: Minimum Triangle Area  
« Reply #5 on: Feb 2nd, 2004, 12:07pm »
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Grin Hee... i spent hours thinking there is something wrong with the problem and then I realised I was considering 'n' as the perimeter all the time keke.. Ok back to board for solving this again!!!
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Icarus
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Re: Minimum Triangle Area  
« Reply #6 on: Feb 2nd, 2004, 3:50pm »
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Perhaps I should remove the posts that deal only with correcting the original problem statement, but then again, T&B has lost too many posts lately without me purposely deleting them! Cheesy
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Sameer
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Re: Minimum Triangle Area  
« Reply #7 on: Feb 25th, 2004, 9:02am »
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Ok so I just approached it with simple trigonometric formulas and came up with this equation and am at stalemate
 
2nA + (A/2n)*( (A/2n) - (n2+n1/5)2 = bc( (A/2n) - (n2+n1/5))
 
I don't know where to go from here. Anyone?
 
Also there can be other method ? Huh
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Re: Minimum Triangle Area  
« Reply #8 on: Feb 27th, 2004, 7:22am »
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on Feb 25th, 2004, 9:02am, Sameer wrote:
Also there can be other method ? Huh

You may try to use the parametric equations (3)-(7) at Mathworld's page on Heronian's triangles.
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Re: Minimum Triangle Area  
« Reply #9 on: Mar 8th, 2004, 3:39pm »
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Sameer, also do not forget the limitations on the relative size of a, b, and c.  Neither of them can be larger than the sum of the other two.
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Sameer
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Re: Minimum Triangle Area  
« Reply #10 on: Mar 9th, 2004, 7:52am »
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Hmm I haven't looked at this problem in a while. I shall take a look at it this weekend with Barukh's and aero_guy's hints!!  Cheesy
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Proof is an idol before which the mathematician tortures himself.
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