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japanese temple geometry 2
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Topic: japanese temple geometry 2
(Read 1272 times)
klbarrus
Newbie
Posts: 29
japanese temple geometry 2
«
on:
Jul 27
th
, 2002, 11:20pm »
Quote
Modify
1) r1, the radius of the small circle is the same as it is in problem 1
r1 = a/16
2) r2, the radius of the large circle:
drop a line segment from c2
(a-r2)^2 = (a/2)^2 + (a/2 + r2)^2
which reduces to
r2 = a/6
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