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Topic: japanese temple geometry 2 (Read 1274 times) |
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klbarrus
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Posts: 29
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japanese temple geometry 2
« on: Jul 27th, 2002, 11:20pm » |
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1) r1, the radius of the small circle is the same as it is in problem 1 r1 = a/16 2) r2, the radius of the large circle: drop a line segment from c2 (a-r2)^2 = (a/2)^2 + (a/2 + r2)^2 which reduces to r2 = a/6
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