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Topic: 12 balls (Read 3746 times) |
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mikedagr8
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A rich man is one who is content; not wealthy.
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Guys i apologise for writing so many threads, but i am excited and want to hear other peoples responses. My answer is 4 weighs. I do this by seperating into 2 groups of 6. then selecting weighing these 2 groups. then i break this group of 6 up into 2 and measure. if the odd ball is in a group it will show. i select the odd group. then i select 2 balls and weigh. record the result then switch a ball. and record. then i look for the odd one out. This of course is the lowest i could find, if at the second stage when i am weighing two groups of 3, adn they are equal i go to the other group and do the same.
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"It's not that I'm correct, it's that you're just not correct, and so; I am right." - M.P.E.
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mikedagr8
Uberpuzzler
A rich man is one who is content; not wealthy.
Gender:
Posts: 1105
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Re: 12 balls
« Reply #2 on: Jul 13th, 2007, 3:58am » |
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does this mean i am correct? that is the smallest? because i know the variation where there is a thousand balls.
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"It's not that I'm correct, it's that you're just not correct, and so; I am right." - M.P.E.
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towr
wu::riddles Moderator Uberpuzzler
Some people are average, some are just mean.
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Re: 12 balls
« Reply #3 on: Jul 15th, 2007, 8:17am » |
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on Jul 13th, 2007, 3:58am, mikedagr8 wrote:does this mean i am correct? |
| If three equals four, yes. I haven't checked Three weighings is enough to find the ball with different weight. With four you can also find out if it's heavier or lighter, but you don't need to know that.
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Wikipedia, Google, Mathworld, Integer sequence DB
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mikedagr8
Uberpuzzler
A rich man is one who is content; not wealthy.
Gender:
Posts: 1105
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Re: 12 balls
« Reply #4 on: Jul 15th, 2007, 5:01pm » |
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a simple yes or no is good enough for me. But yeah, i screwed up in working out, but i knew thre answer.
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"It's not that I'm correct, it's that you're just not correct, and so; I am right." - M.P.E.
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Aryabhatta
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Re: 12 balls
« Reply #5 on: Jul 15th, 2007, 6:05pm » |
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on Jul 15th, 2007, 5:01pm, mikedagr8 wrote:a simple yes or no is good enough for me. But yeah, i screwed up in working out, but i knew thre answer. |
| If you are talking about weighing 6 balls each first, your answer is wrong. Putting 6 balls against each other gives no information at all and is pretty useless. And for your yes/no question, Yes, three is the correct answer and No, four is not the right answer.
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« Last Edit: Jul 15th, 2007, 6:05pm by Aryabhatta » |
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