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Topic: A Cubic And Inscribed Problem? (Read 649 times) |
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K Sengupta
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A Cubic And Inscribed Problem?
« on: Feb 4th, 2006, 11:39pm » |
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I am looking for a solution to the undernoted problem.
PROBLEM:
A hexagon is inscribed in a circle with radius r. Two of it's sides have length 2 and the last two have length 3.
Prove that r is a root of the equation:
2r3- 7r- 3= 0 .
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Barukh
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Re: A Cubic And Inscribed Problem?
« Reply #1 on: Feb 5th, 2006, 4:17am » |
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I don't think the data given is sufficient to deduce the required answer.
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Sjoerd Job Postmus
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Posts: 228
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Re: A Cubic And Inscribed Problem?
« Reply #2 on: Feb 5th, 2006, 7:46am » |
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on Feb 4th, 2006, 11:39pm, K Sengupta wrote:I am looking for a solution to the undernoted problem.
PROBLEM:
A hexagon is inscribed in a circle with radius r. Two of it's sides have length 2 and the last two have length 3.
Prove that r is a root of the equation:
2r3- 7r- 3= 0 .
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Let's imagine, just for the fun of it... that the other two sides are 300 and 301, for the fun of it. This'd give an answer. But, what if the two sides are 400 and 401, that'd give a totally different answer!
So, I must say, I can not solve it... too many ungivens. (not enough givens)
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pex
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Re: A Cubic And Inscribed Problem?
« Reply #4 on: Feb 5th, 2006, 1:47pm » |
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It does seem to work if both other sides have length 1.
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