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Topic: THE COEFFICIENT OF x^2 (Read 1248 times) |
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pcbouhid
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THE COEFFICIENT OF x^2
« on: Nov 29th, 2005, 8:30am » |
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Find the coefficient of x^2 upon the expansion and collecting of the terms in this expression: ((((x - 2)^2 - 2)^2 - 2)^2 - .....- 2)^2 ------------------------------------ (n times)
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« Last Edit: Nov 29th, 2005, 8:34am by pcbouhid » |
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Joe Fendel
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Re: THE COEFFICIENT OF x^2
« Reply #1 on: Nov 29th, 2005, 9:22am » |
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If I had to guess, I'd say (4(2n-1) - 4(n-1)) / 3.
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Eigenray
wu::riddles Moderator Uberpuzzler
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Re: THE COEFFICIENT OF x^2
« Reply #2 on: Nov 29th, 2005, 10:13am » |
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Well, no reason not to prove your guess: hidden: | If a'+b'x+c'x2 = (a-2+bx+cx2)2 (mod x3), then a'=(a-2)2, b'=2(a-2)b, and c'=2(a-2)c+b2. If we start with (a0,b0,c0) = (0,1,0), then (a1,b1,c1) = (4, -4, 1). Since a1=4, we have an=4 for all n>0, so we can rewrite the recurrence as b' = 4b, c' = 4c + b2. Then clearly bn = -4n, so this becomes cn+1 = 4cn + 42n, and c1=1. This recurrence has the unique solution cn = (42n-1-4n-1)/3. |
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pcbouhid
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Re: THE COEFFICIENT OF x^2
« Reply #3 on: Nov 30th, 2005, 10:31am » |
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It seems a good team work with two members: the first make a guess, and the second, prove the guess. Next time, in separate rooms!!!!!!!!!!!!
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srn437
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Re: THE COEFFICIENT OF x^2
« Reply #4 on: Sep 17th, 2007, 6:03pm » |
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What if you replaced n with x?
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ThudnBlunder
wu::riddles Moderator Uberpuzzler
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Re: THE COEFFICIENT OF x^2
« Reply #5 on: Sep 17th, 2007, 7:14pm » |
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on Sep 17th, 2007, 6:03pm, srn347 wrote:What if you replaced n with x? |
| What type of number is n? What type of number is x?
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srn437
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Re: THE COEFFICIENT OF x^2
« Reply #6 on: Sep 17th, 2007, 8:49pm » |
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Ask pcbouhid.
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