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Topic: Filling the Box (Read 491 times) |
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Sebastian Craine
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Since you spoke of a rectangular box, it is safe to assume the solid might be a cube (not that it matters). You failed to stipulate that one would need to fill the box with a finite number of incongruent cubes, as it is plausible if you would have an infinite number. Let the box be a square with side length N. Then fill the box with incongruent cubes with side lengths that are part of an infinite sequence with sum N.
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Icarus
wu::riddles Moderator Uberpuzzler
Boldly going where even angels fear to tread.
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Posts: 4863
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Re: Filling the Box
« Reply #1 on: Aug 22nd, 2005, 5:58pm » |
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You are mixing dimensions. Your solutions works for filling a one dimensional "box". It does not work in 2 or higher dimensions, though. There is already a thread for this puzzle. You may find the discussion there illuminating.
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"Pi goes on and on and on ... And e is just as cursed. I wonder: Which is larger When their digits are reversed? " - Anonymous
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