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Topic: Maximizing the Daytime (Read 4290 times) |
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Barukh
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Maximizing the Daytime
« on: Aug 13th, 2013, 3:39am » |
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I suddenly came to the following interesting (IMO) question. Although not completely correct, define Daytime at a certain location, specific day as time interval between sunrise and sunset (if the first doesn't occur, define it to be 0; if the second doesn't occur - 24 hours). Then, we can define Year Daytime (I admit it’s a bad name) as the sum of the Daytimes over a calendar year. It seems that several interesting questions may be asked about Year Daytime. Here’re a few: 1. At a given location, is Year Daytime a constant? 2. Which location(s) maximize/minimize Year Daytime? For those who find it interesting, the following link might be relevant.
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Grimbal
wu::riddles Moderator Uberpuzzler
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Re: Maximizing the Daytime
« Reply #1 on: Aug 20th, 2013, 9:02am » |
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1. I think it depends how exactly you define "sunrise" and "sunset". 2. max at L1, min at L2
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Barukh
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Re: Maximizing the Daytime
« Reply #2 on: Aug 23rd, 2013, 10:11pm » |
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on Aug 20th, 2013, 9:02am, Grimbal wrote:1. I think it depends how exactly you define "sunrise" and "sunset". |
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Grimbal
wu::riddles Moderator Uberpuzzler
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Re: Maximizing the Daytime
« Reply #3 on: Aug 26th, 2013, 7:31am » |
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I was referring to Lagrange points. With the definition you mention, the visible part of the sky is a bit more than an hemisphere. Without any math, I guess you optimize the dayligh on the arctic circles. You benefit from full days in the summer, without loosing all light near the winter solstice.
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« Last Edit: Aug 26th, 2013, 7:44am by Grimbal » |
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Barukh
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Re: Maximizing the Daytime
« Reply #4 on: Aug 29th, 2013, 12:27am » |
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Grimbal, your intuition and/or knowledge of astronomy is exemplifying! I did it the hard way (experimentally). It turns out that - taken into account another parameter of Earth’s orbit – the average daytime is maximized at just one arctic circle. A follow-up question: where is it minimized?
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