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   Evaluate Sum
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   Author  Topic: Evaluate Sum  (Read 1305 times)
Benny
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Evaluate Sum  
« on: Mar 17th, 2012, 9:59am »
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n=1 to infinity SUM (48n)/(n^4+4)
 
= 12/(n^2 - 2n+2) - 12/(n^2 + 2n+2)
 
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pex
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Re: Evaluate Sum  
« Reply #1 on: Mar 17th, 2012, 1:18pm »
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on Mar 17th, 2012, 9:59am, Benny wrote:
n=1 to infinity SUM (48n)/(n^4+4)
 
= 12/(n^2 - 2n+2) - 12/(n^2 + 2n+2)

It's ... eighteen ...
 
Hint: Complete the squares in the denominators of your last expression, and telescope.
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Benny
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Re: Evaluate Sum  
« Reply #2 on: Mar 20th, 2012, 11:17am »
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Thanks. I don't know how I missed that.
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