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Topic: Triangles (Read 873 times) |
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codpro880
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Equilateral triangle ABC has altitudes BX and AY that intersect at point P. QR, containing point P, is parallel to AC. What fraction of the area of triangle ABC is the triangle PYR? Explain thoroughly. (I realize I don't have R labeled )
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towr
wu::riddles Moderator Uberpuzzler
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Re: Triangles
« Reply #1 on: Mar 3rd, 2009, 12:45pm » |
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1/4th Because P is the center of the equilateral triangle, and so QR is half of AC and QR=QX=XR, which divide the triangle in 4 equal pieces.
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« Last Edit: Mar 3rd, 2009, 12:59pm by towr » |
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SMQ
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Re: Triangles
« Reply #2 on: Mar 3rd, 2009, 12:53pm » |
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on Mar 3rd, 2009, 12:45pm, towr wrote:1/4th [...] QR is half of AC |
| Come again?! P is indeed the center of the equilateral triangle, but QR = (2/3)AC, so PR = AC/3. Moreover, since angle PYR is right, triangle PYR is 30-60-90 with hypotenuse AC/3, and thus half of an equilateral triangle with side AC/3. Such a triangle would have area 1/9 ABC, so triangle PYR has 1/18 the area of ABC. --SMQ
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--SMQ
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towr
wu::riddles Moderator Uberpuzzler
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Re: Triangles
« Reply #3 on: Mar 3rd, 2009, 12:59pm » |
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on Mar 3rd, 2009, 12:53pm, SMQ wrote: Come again?! |
| Yeah, sorry. I shouldn't be answering puzzles during the opening credits of anime.. [edit]Let alone answering something that isn't even the question[/edit]
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« Last Edit: Mar 3rd, 2009, 1:01pm by towr » |
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codpro880
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Re: Triangles
« Reply #4 on: Mar 3rd, 2009, 5:56pm » |
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Yes SMQ. hahaha towr.
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Grimbal
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I count 18.
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