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   Author  Topic: 7^1000  (Read 597 times)
codpro880
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7^1000  
« on: Feb 26th, 2009, 11:44am »
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What is the number in the units place in 7^1000? Why?
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Re: 7^1000  
« Reply #1 on: Feb 26th, 2009, 12:03pm »
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Well, 74 = 1 (mod 10), so 71000 = 1250 = 1 (mod 10), right?
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Re: 7^1000  
« Reply #2 on: Feb 26th, 2009, 12:04pm »
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A similar thread: http://www.ocf.berkeley.edu/~wwu/cgi-bin/yabb/YaBB.cgi?board=riddles_eas y;action=display;num=1210461451
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codpro880
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Re: 7^1000  
« Reply #3 on: Feb 26th, 2009, 5:31pm »
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Yes, 1 is the correct answer. I don't understand the mod stuff though :/. I need more schooling.
 
The way I solved the problem was by noticing that the powers of seven repeat the digits in the unit place in a pattern.  
7^1=7
7^2=49
7^3=343
7^4=2401
7^5=16807
7^6=117649
etc.
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Re: 7^1000  
« Reply #4 on: Feb 26th, 2009, 10:51pm »
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on Feb 26th, 2009, 5:31pm, codpro880 wrote:
I don't understand the mod stuff though :/

http://en.wikipedia.org/wiki/Modular_arithmetic is a good place to start. (Please note that officially, I used the "=" sign inappropriately; it should be something like "=".)
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Re: 7^1000  
« Reply #5 on: Mar 2nd, 2009, 8:10am »
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on Feb 26th, 2009, 10:51pm, pex wrote:
I used the "=" sign inappropriately; it should be something like "=".)

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codpro880
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Re: 7^1000  
« Reply #6 on: Mar 2nd, 2009, 11:08am »
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So it's kind of like using different number bases except you go in a circle?
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Re: 7^1000  
« Reply #7 on: Mar 2nd, 2009, 11:31am »
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on Mar 2nd, 2009, 11:08am, codpro880 wrote:
So it's kind of like using different number bases except you go in a circle?
Yes, that's a good way to look at it.
Just like using a clock, also. Add 24 hours and you get the same time again.
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codpro880
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Re: 7^1000  
« Reply #8 on: Mar 2nd, 2009, 3:53pm »
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on Feb 26th, 2009, 12:03pm, pex wrote:
Well, 74 = 1 (mod 10), so 71000 = 1250 = 1 (mod 10), right?

 
I still don't get pex's logic  Huh
« Last Edit: Mar 2nd, 2009, 3:56pm by codpro880 » IP Logged

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River Phoenix
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Re: 7^1000  
« Reply #9 on: Mar 2nd, 2009, 5:16pm »
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on Mar 2nd, 2009, 3:53pm, codpro880 wrote:

 
I still don't get pex's logic  Huh

 
multiplication still works in a modulus number system, it just loops around.
so since 7^4 = 1 (mod 10), therefore 7^8 = 1 * 1 = 1 (mod 10), etc.
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