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   Author  Topic: Difficult item  (Read 524 times)
Karotto
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Difficult item  
« on: Jun 29th, 2008, 3:34am »
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Can you solve this? (Click the image for zoom)
 

 
Thanks
« Last Edit: Jun 29th, 2008, 3:35am by Karotto » IP Logged
Wardub
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Re: Difficult item  
« Reply #1 on: Jun 29th, 2008, 5:58am »
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My guess is A.
 
Labeling the squares as follows
123
456
789
 
Reasoning:
It looks like the pairs across each other are the same, and the blue circles total 3.
 
If you look at(2,Cool (4,6) (3,7) there the same image and blue dots = 3.
 
Now 1 has 2 dots on top then 1 on the bottom with 0 blue dots.
So number 9 should be the same image as 1 with 3 dots.  A has 3 dots and 3 blue dots, but its upside down.  So really the pairs aren't the same but they are flipped over a horizontal axis.

 
Or maybe I am out of my mind, and that only made sense to me.  
 Huh
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Immanuel_Bonfils
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Re: Difficult item  
« Reply #2 on: Jun 29th, 2008, 11:53am »
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A, for a central symmetry.
 
I didn't notice the blue dots. Let us think about...
 
Seems that the number of blue dotas must be three for each symmetric pair.
 
I just don undestand why this problem is hard?
« Last Edit: Jun 29th, 2008, 12:00pm by Immanuel_Bonfils » IP Logged
Hippo
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Re: Difficult item  
« Reply #3 on: Jun 29th, 2008, 12:35pm »
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But why on 7 there are 2 blue dots? And why the positioning of blue dots changes ... and yes, it does not belong to hard.
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towr
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Re: Difficult item  
« Reply #4 on: Jun 29th, 2008, 2:29pm »
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on Jun 29th, 2008, 11:53am, Immanuel_Bonfils wrote:
I just don undestand why this problem is hard?
Because some people, when they first come here, think that the definition of hard is "I don't know the answer". And of course reading someone's mind, as puzzles of this kind sort of require, is hard.
« Last Edit: Jun 29th, 2008, 2:33pm by towr » IP Logged

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