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Topic: Analog Clock II (Read 562 times) |
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osirusblue
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Analog Clock II
« on: Aug 29th, 2007, 12:05am » |
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Is my thinking flawed that there are 11 times the hands of clock will be on top of each other?
I had been told that it was 10 but for the life of me I can only make it make sense if I say 11.
1:05
2:10
3:15
4:20
5:25
6:30
7:35
8:40
9:45
10:50
11:55
No? I understand the AM/PM changes it a bit but if we say just within a 12 hour period?
Sorry if I should have hidden any of this... first time caller here.
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mikedagr8
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A rich man is one who is content; not wealthy.
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Re: Analog Clock II
« Reply #1 on: Aug 29th, 2007, 12:08am » |
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No it's 11.
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"It's not that I'm correct, it's that you're just not correct, and so; I am right." - M.P.E.
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towr
wu::riddles Moderator
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Some people are average, some are just mean.
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Re: Analog Clock II
« Reply #2 on: Aug 29th, 2007, 12:29am » |
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The little hand makes one round, the large hand makes 12, so it has to pass the little one 11 times.
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Wikipedia, Google, Mathworld, Integer sequence DB
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osirusblue
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Re: Analog Clock II
« Reply #3 on: Aug 30th, 2007, 12:11am » |
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That's what I thought. Thank you both. Now, I must be beating somebody for making me think I was losing my mind!
Cheers!
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rmsgrey
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Re: Analog Clock II
« Reply #4 on: Aug 30th, 2007, 2:26am » |
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on Aug 29th, 2007, 12:05am, osirusblue wrote:1:05
2:10
3:15
4:20
5:25
6:30
7:35
8:40
9:45
10:50
11:55 |
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Those times aren't exact - it's actually 1:05:27.2727... between overlaps - in particular, the last time on the list should actually be 12:00 again.
Depending on the exact phrasing of the question, considering the 12 hour interval from noon to midnight (or midnight to noon), the number of times the two hands coincide could be 10, 11, or 12, according to whether you count one, both, or neither 12 o'clocks.
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