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Topic: Math riddle that I can't solve... (Read 516 times) |
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TyrantSlaughter
Newbie
Posts: 1
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Math riddle that I can't solve...
« on: Jul 30th, 2007, 8:22pm » |
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Hey guys, I'm new, and I'm sorry if this was posted before.
3 men stay at a motel and the manager charges them $10 each (a total of $30). After a while the manager calls the bell boy over and says he overcharged the men saying they should have paid only $25. So he gives the bell boy $5 to take back to them.
Along the way, the bell boy decides to keep $2 for himself, so he gives them $3 back ($1 each). So that means each man paid $9.
Now, we have $9 for each man, giving us $27, and the bell boy kept $2, giving us $29. Where did the last dollar go?"
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towr
wu::riddles Moderator
Uberpuzzler
Some people are average, some are just mean.
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Posts: 13730
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Re: Math riddle that I can't solve...
« Reply #1 on: Jul 30th, 2007, 11:47pm » |
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You could just write it out
step 0:
man 1: 10$
man 2: 10$
man 3: 10$
manager: 0$
bell boy: 0$
step 1:
man 1: 10$-10$ = 0$
man 2: 10$-10$ = 0$
man 3: 10$-10$ = 0$
manager: +30$
bell boy: 0$
step 2:
man 1: 0$
man 2: 0$
man 3: 0$
manager: +30$ -5$ = 25$
bell boy: 0$ + 5$ = 5$
step 3:
man 1: 0$ + 1$ = 1$
man 2: 0$ + 1$ = 1$
man 3: 0$ + 1$ = 1$
manager: 25$
bell boy: 5$ -3$ = 2$
Also consider the alternate question: Each man paid 9$, the manager kept 25$, so that's a total of 52$, where did that 22$ extra come from?
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jollytall
Senior Riddler
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Posts: 585
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Re: Math riddle that I can't solve...
« Reply #2 on: Jul 31st, 2007, 12:50am » |
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It was posted many times.
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srn437
Newbie
the dark lord rises again....
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Re: Math riddle that I can't solve...
« Reply #3 on: Aug 26th, 2007, 9:26pm » |
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In the initial equation you don't add the 2. You subtract it. They paid 25.
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