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Topic: E8 (Read 683 times) |
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Grimbal
wu::riddles Moderator
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Find a nine-digit number made up of 1,2,3,4,5,6,7,8,9 in some permutation such that when digits are removed one at a time from the right the number remaining is divisible in turn by 8, 7, 6, 5, 4, 3, 2, 1.
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C.S.I.
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Can anyone help me think outside the box please?
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Re: E8
« Reply #1 on: Apr 20th, 2007, 10:48am » |
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381654729
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Grimbal
wu::riddles Moderator
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Re: E8
« Reply #2 on: Apr 20th, 2007, 10:57pm » |
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Correct. 
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xpectronum
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Re: E8
« Reply #3 on: Jan 5th, 2008, 4:47am » |
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i find it hard to solve using hit n trial. can it be solved without using a calculator / computer?
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mikedagr8
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A rich man is one who is content; not wealthy.
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Re: E8
« Reply #4 on: Jan 5th, 2008, 5:04am » |
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Yes. The first step is that you know when dividing by five the number must either be 0 or 5. But since there's no 0...
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"It's not that I'm correct, it's that you're just not correct, and so; I am right." - M.P.E.
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Grimbal
wu::riddles Moderator
Uberpuzzler
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Posts: 7527
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Re: E8
« Reply #5 on: Jan 5th, 2008, 5:55am » |
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Then, evens must be at even places.
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