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   6-Digit Number
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   Author  Topic: 6-Digit Number  (Read 659 times)
ThudnBlunder
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6-Digit Number  
« on: Jun 27th, 2004, 4:13pm »
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Can you find a 6-digit number without writing a computer program such that:  
 
(i) The first 3 digits minus last 3 digits = 665.  
(ii) Within the number there is a 3 to the left of a 1.  
(iii) There is a 7 to the right of a 9.  
(iv) There is a 5 to the left of a 3.  
(v) There is a 0.  
 
« Last Edit: Jun 28th, 2004, 10:25am by ThudnBlunder » IP Logged

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Grimbal
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Re: 6-Digit Number  
« Reply #1 on: Jun 27th, 2004, 4:26pm »
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Yes.
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ThudnBlunder
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Re: 6-Digit Number  
« Reply #2 on: Jun 27th, 2004, 4:30pm »
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That's that settled then.  
 
  Roll Eyes
 
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Noke Lieu
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Re: 6-Digit Number  
« Reply #3 on: Jun 27th, 2004, 6:27pm »
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Nice to see honour in action.
 
this got me to thinking, and I don't think it really warrants its own thread, so I'll tag it on here. (and not sure I've seen it)
 
A number, starting with two abritary digits, such that these two digits can be used to produce the third digit. Then the second and third used to produce the fourth.....  
can only use each digit once. AND we're only staying decimal. Except maybe for an extension...
 
eg: 3257 (3+2=5; 5+2=7) or 8426
 
What is the biggest number that satisfies these requirements?
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Leo Broukhis
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Re: 6-Digit Number  
« Reply #4 on: Jun 27th, 2004, 8:49pm »
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Noke,
I got ::86235::
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Noke Lieu
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Re: 6-Digit Number  
« Reply #5 on: Jun 28th, 2004, 3:53am »
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9 pm, and still at work. Better go home before they switch the alarms on.
 
Leonid Broukhis, mine's bigger. Roll Eyes
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Grimbal
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Re: 6-Digit Number  
« Reply #6 on: Jun 28th, 2004, 6:35am »
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I got 2 6-digit numbers.
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Leo Broukhis
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Re: 6-Digit Number  
« Reply #7 on: Jun 28th, 2004, 9:52am »
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What operations are allowed? Can division be inexact?
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Grimbal
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Re: 6-Digit Number  
« Reply #8 on: Jun 28th, 2004, 10:09am »
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Ahaaa, but with integer operations I get a much longer one.  Smiley
 
::972365410
9-7=2, 7/2=3, 2*3=6, 3^6=5, 6&5=4, 5-4=1, 4%1=0
(^ is xor)
::
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Leo Broukhis
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Re: 6-Digit Number  
« Reply #9 on: Jun 28th, 2004, 11:21am »
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So much for incomplete specifications. I limited myself to addition, subtraction, multiplication and division with no remainder.
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Noke Lieu
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Re: 6-Digit Number  
« Reply #10 on: Jun 28th, 2004, 11:03pm »
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Yeah, I'm with you, Leonid Broukhis. Multiplying, dividing, subtracting and addition. No remainders.
 
Unsurprisingly, am stuck at 5 digits in decimal....
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Eigenray
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Re: 6-Digit Number  
« Reply #11 on: Jun 29th, 2004, 6:05am »
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There are 2 of length 6, 16 of length 5, 40 of length 4, and 72 of length 3 . . .
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Grimbal
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Re: 6-Digit Number  
« Reply #12 on: Jun 29th, 2004, 8:33am »
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Same number of solutions here: 2x6, 16x5, 40x4, 72x3, 90x2 and 10x1.
And surprise, surprise, one 6-digit number is just the reverse of the other!   Shocked
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Leo Broukhis
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Re: 6-Digit Number  
« Reply #13 on: Jun 29th, 2004, 10:03am »
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I've made a mistake in my hand-drawn graph. Perl rules!
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