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Topic: magic 100 (Read 530 times) |
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Noke Lieu
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Okay, its similar to magic 19. Probably a bit easier.
besides, I can actually go to my boss with these to show I'm working! Great job...
Numbers 1-24
Each Octogon has a total of 100. Square in the middle has 50.
(haven't figured this bit out yet...)
How many magic totals (T) where square has total T/2?
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Noke Lieu
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pen... paper... let's go! (and bit of plastic)
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Re: magic 100
« Reply #1 on: Apr 29th, 2004, 8:19pm » |
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actually, I'm struggling with the second part. Oh, for ANY programming knowledge (other than my VCR) 
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Noke Lieu
Uberpuzzler
pen... paper... let's go! (and bit of plastic)
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Re: magic 100
« Reply #2 on: Feb 6th, 2005, 8:42pm » |
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Thought I might revive this before it slides into oblivion.
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John_Gaughan
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Re: magic 100
« Reply #3 on: Feb 7th, 2005, 5:37am » |
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Any hints?
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x = (0x2B | ~0x2B)
x == the_question
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Noke Lieu
Uberpuzzler
pen... paper... let's go! (and bit of plastic)
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Re: magic 100
« Reply #4 on: Feb 8th, 2005, 6:16pm » |
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Depends what you're after, and where your skills lie. For programming, no. I can't provide hints. I don't have the skills myself.
For brute force mixed with a tad of reasoning, yeah that's my forte. (pen... paper... lets go) The best one/most obvious one would be print out the picture. Tear 24 bits of paper, number them; slide them around. Start at the middle, probably 
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towr
wu::riddles Moderator
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Re: magic 100
« Reply #5 on: Feb 9th, 2005, 12:39am » |
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Well, all the rings together add up to 450, and all the numbers added up together to 300. You can do something with that as a hint.
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Wikipedia, Google, Mathworld, Integer sequence DB
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Noke Lieu
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Re: magic 100
« Reply #6 on: Feb 9th, 2005, 5:36pm » |
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good point. Check out the immaculation dissection of magic nineteen
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Grimbal
wu::riddles Moderator
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Re: magic 100
« Reply #7 on: Feb 10th, 2005, 1:46am » |
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Actually, there are 5 equation and 24 unknowns. That can not be so hard, except that they must be all different.
Here is a solution for T=100.
::
__ 18 __ 17 __ 01 __ 02 __
08 __ __ __ 16 __ __ __ 24
__ __ __ __ __ __ __ __ __
07 __ __ __ 11 __ __ __ 23
__ 10 __ 13 __ 14 __ 09 __
19 __ __ __ 12 __ __ __ 03
__ __ __ __ __ __ __ __ __
20 __ __ __ 15 __ __ __ 04
__ 06 __ 05 __ 21 __ 22 __::
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ThudnBlunder
wu::riddles Moderator
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Re: magic 100
« Reply #8 on: Feb 10th, 2005, 8:26am » |
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Quote:Actually, there are 5 equation That can not be so hard, except that they must be all different.
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...and consecutive, beginning with 1
Hence, there are 6 equations.
SIGMA a to x = 300
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| « Last Edit: Feb 10th, 2005, 8:30am by ThudnBlunder » |
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