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Topic: Two Easy Riddles & Two Word Problems (Read 1304 times) |
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Joe
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Two Easy Riddles & Two Word Problems
« on: Sep 21st, 2003, 3:55pm » |
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1.People have it - girls and ladies always, men and boys never, althought Larry certianly had it first, and Bill had is twice. What is it?
2.On the galleon there were a number of ship's cats, a number of pirates, the cook, and the one-legged captain. Altogether therer were 15 heads and 41 legs. How many ships cats were there.
3.By the time the sailing ship had made five voyages, it had carried a total of 500 passengers. There were 190 passengers altogether on the forst two voyages, 155 passengers altogether on the seconds and third voyages, 210 passengers altogether on the third and fourth voyages, and 225 passengers altogeth on the fourth and fifty voyages. How many passengers were on the ship on its third voyage?
4.One of the men coming out of the catina was overheard to say to other, "There are two bandits in there, and one of them is the father of the other's son!" Can you explain how this could happen?
//Title changed and Thread moved from the Hard Forum by Icarus - Please use descriptive titles.
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| « Last Edit: Sep 21st, 2003, 8:48pm by Icarus » |
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Icarus
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Re: Two Easy Riddles & Two Word Problems
« Reply #1 on: Sep 21st, 2003, 9:07pm » |
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I'll give you some hints Joe. Use your mouse to select the hidden text in order to read it. (CTRL-A will select everything).
1) Hint: This puzzle is about spelling.
2) Hint: The cook and the captain provide 2 heads and 3 legs, leaving 13 and 38 left. Let C = # of cats, P = # of pirates. Counting total heads of cats & pirates and counting total legs of cats & pirates gives you a set of two equations in two unknowns. Solve it to find the number of cats.
3) Hint: Let p, q, r, s, t be the number of passengers on the each of the 5 trips, in order. The first thing you are told is that p+q+r+s+t = 500. Next is p+q = 190, q+r=155, r+s=210, and s+t=225. This gives 5 equations in 5 unknowns, so you can solve it to find r.
4) Hint: This riddle relies on cultural biases people have. This is only puzzling if you assume something about the thieves. Remove that assumption, and the only thing that doesn't make sense is why anyone would make such an odd remark about the situation.
Note: Since I know nothing about you, Joe, I may have assumed more mathematical knowledge in my hints on 2 and 3 than you currently possess. If this is the case, let me know.
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Speaker
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Re: Two Easy Riddles & Two Word Problems
« Reply #2 on: Sep 22nd, 2003, 1:10am » |
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1: Lads and lasses have it, but kids do not.
2: There is one more pirate than cats.
3: Who knows
4: May 11, 2003.
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| « Last Edit: Sep 22nd, 2003, 1:40am by Speaker » |
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Sir Col
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Re: Two Easy Riddles & Two Word Problems
« Reply #3 on: Sep 22nd, 2003, 5:31am » |
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on Sep 21st, 2003, 9:07pm, Icarus wrote:| I'll give you some hints Joe. Use your mouse to select the hidden text in order to read it. (CTRL-A will select everything). |
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I hadn't throught about CTRL-A; nice tip, Icarus.
Alternatively, you can triple click the post! 
Quote:| 3) Hint: Let p, q, r, s, t be the number of passengers on the each of the 5 trips, in order. The first thing you are told is that p+q+r+s+t = 500. Next is p+q = 190, q+r=155, r+s=210, and s+t=225. This gives 5 equations in 5 unknowns, so you can solve it to find r. |
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Actually, it's a bit easier than it first appears...
As p+q=190 and s+t=225, p+q+s+t=415. So, (p+q+r+s+t)–(p+q+s+t)=r=500–415=85.
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Icarus
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Re: Two Easy Riddles & Two Word Problems
« Reply #4 on: Sep 22nd, 2003, 7:45pm » |
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on Sep 22nd, 2003, 1:10am, Speaker wrote:
Okay, Speaker, you've got me. What is that about?
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And e is just as cursed.
I wonder: Which is larger
When their digits are reversed? " - Anonymous
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aero_guy
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Re: Two Easy Riddles & Two Word Problems
« Reply #5 on: Sep 23rd, 2003, 1:50pm » |
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I am assuming it is a cetain holiday...
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Re: Two Easy Riddles & Two Word Problems
« Reply #6 on: Sep 23rd, 2003, 4:16pm » |
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Yes, a certain holiday. I first thought this was one of those "at least one of the others..." kind of puzzles. But, after posting and looking at it in print, the real answer came to light.
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Icarus
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Re: Two Easy Riddles & Two Word Problems
« Reply #7 on: Sep 23rd, 2003, 5:52pm » |
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Okay - I get it now. Since Joe hasn't said anything, I'm wondering if I lost him by the twin renaming and moving of his thread. (It was originally named something like "PLEASE, I NEED HELP, QUICK!!"). Perhaps I should have done the two fixes one at a time.
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"Pi goes on and on and on ...
And e is just as cursed.
I wonder: Which is larger
When their digits are reversed? " - Anonymous
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Speaker
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Re: Two Easy Riddles & Two Word Problems
« Reply #8 on: Sep 23rd, 2003, 6:04pm » |
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I think your fix was fine. There is still a link in the Hard section with the original title, so he should be able to find the new thread.
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They that can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety. <Ben Franklin>
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Icarus
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Re: Two Easy Riddles & Two Word Problems
« Reply #9 on: Sep 23rd, 2003, 7:09pm » |
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Actually, no - the "moved" post in the hard forum is under the new name. I made the mistake of first renaming it, then moving. If I had done it the other way around, it would be under the original name there, and I could have changed the message (which is produced automatically) to indicate the name change as well.
Now though, I don't remember exactly what the original name was, so there isn't much point in changing the name of the "moved" message back. If Joe doesn't post again in the next couple weeks, I'll delete the "moved" thread anyway. Those things are pointless after awhile.
(He may also be put out at my calling riddles that obviously left him stumped "easy", but it's clear that these riddles are more in the line of others in the Easy forum than anything in the Hard. If the first were by iself, I would have moved it to the "What Am I" forum.)
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"Pi goes on and on and on ...
And e is just as cursed.
I wonder: Which is larger
When their digits are reversed? " - Anonymous
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Sameer
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Re: Two Easy Riddles & Two Word Problems
« Reply #10 on: Oct 1st, 2003, 8:23am » |
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I am still lost on 4... 
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BNC
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Re: Two Easy Riddles & Two Word Problems
« Reply #11 on: Oct 1st, 2003, 12:49pm » |
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on Oct 1st, 2003, 8:23am, Sameer wrote:| I am still lost on 4... |
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Sameer,
Here's a BIG hint:Saying that A is B's son, may mean more than one thing about B.
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How about supercalifragilisticexpialidociouspuzzler [Towr, 2007]
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Smart Guy
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Re: Two Easy Riddles & Two Word Problems
« Reply #12 on: Oct 3rd, 2003, 3:11am » |
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4: The two bandits are a man and a women, parents of the son.
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jtrook
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Re: Two Easy Riddles & Two Word Problems
« Reply #13 on: Oct 3rd, 2003, 8:46am » |
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I enjoyed the first three questions. The second and third I with my 9th grade algebra class. They will make excellent warm up problems.
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Nikolina Demark
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Re: Two Easy Riddles & Two Word Problems
« Reply #14 on: Nov 21st, 2003, 10:24am » |
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I know the answer to No1. It's the letter L! Twice in BiLL, once in Larry, girLs and Ladies have it, men and boys don't. Hurray! 
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rmsgrey
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Re: Two Easy Riddles & Two Word Problems
« Reply #15 on: Nov 22nd, 2003, 9:28pm » |
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Alternate for 4: Adoption.
And then you get the SF explanations...
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