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Topic: Matches time again (Read 592 times) |
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BNC
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Matches time again
« on: Jul 9th, 2003, 9:53am » |
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Move 3 matches to get a valid equation:
|||| - || = ||||
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Steihl
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||||| - | = ||||
Oh wait I only moved 1 match.
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Guestibe
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Do the same as Steihl, but then swap the two rightmost matches. Total of three matches moved. Err... well, it works in a literal sense anyway.
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WombatDeath
Junior Member
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Re: Matches time again
« Reply #3 on: Jul 9th, 2003, 12:36pm » |
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How's this: |||| - | + | = ||
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| « Last Edit: Jul 9th, 2003, 12:37pm by WombatDeath » |
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SWF
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Re: Matches time again
« Reply #4 on: Jul 9th, 2003, 5:07pm » |
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Moving only 2, but you can always add a trivial move, like moving the first stick in a row of four to the end.
|||| X | = ||||
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mistysakura
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Re: Matches time again
« Reply #5 on: Jul 9th, 2003, 8:34pm » |
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on Jul 9th, 2003, 12:36pm, WombatDeath wrote:
4-1+1=2? How does that work? The only way I can see it worlk is with brackets...
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BNC
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Re: Matches time again
« Reply #6 on: Jul 9th, 2003, 9:17pm » |
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on Jul 9th, 2003, 5:07pm, SWF wrote:Moving only 2, but you can always add a trivial move, like moving the first stick in a row of four to the end.
|||| X | = ||||
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Hehe, of course the 1 match solution is trivial, but I tried to think of a 2-match solution and ask for 1-2-3 solutions, but couldn't. Nice!
I had another 3-match solution in mind, though.
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wowbagger
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Re: Matches time again
« Reply #7 on: Jul 10th, 2003, 2:10am » |
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on Jul 9th, 2003, 9:17pm, BNC wrote:| I had another 3-match solution in mind, though. |
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Maybe this one:
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III / \I I = III
sorry if it doesn't align quite right.
plain math: 3 / sqrt(1) = 3
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| « Last Edit: Jul 10th, 2003, 2:16am by wowbagger » |
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otter
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Re: Matches time again
« Reply #8 on: Jul 10th, 2003, 6:25am » |
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How about X||| - | = X||? Should only be three moves if you count changing || to X as only one move.
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We shall not cease from exploration. And the end of all our exploring will be to arrive where we started
and know the place for the first time.
T.S. Eliot
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WombatDeath
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Re: Matches time again
« Reply #9 on: Jul 10th, 2003, 12:32pm » |
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on Jul 9th, 2003, 8:34pm, mistysakura wrote:
(Removed) How does that work? The only way I can see it worlk is with brackets...
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Well, yes, but after staring at the damn thing for 20 minutes I'm surely entitled to discard such a silly notion as the left-to-right rule.
No? Bah!
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WombatDeath
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Re: Matches time again
« Reply #10 on: Jul 10th, 2003, 12:48pm » |
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OK, here's one that doesn't involve cheating: ||| / ||| = || - |.
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BNC
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Re: Matches time again
« Reply #11 on: Jul 11th, 2003, 1:23am » |
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A note: on second thought, the solution I had in mind, could also be generated moving 2 matches -- it depends on the original spacing between the matches.
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WombatDeath
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Re: Matches time again
« Reply #12 on: Jul 11th, 2003, 12:01pm » |
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on Jul 11th, 2003, 1:23am, BNC wrote:| A note: on second thought, the solution I had in mind, could also be generated moving 2 matches |
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Was it |+|-| = ||/||? That can be achieved in either two or three moves, depending on whether the sixth (or seventh, if you prefer) match is used as the dividing symbol or just stuck on the end of the equation. The first method (two moves) only works if you allow sufficient spacing.
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| « Last Edit: Jul 11th, 2003, 12:03pm by WombatDeath » |
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BNC
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Re: Matches time again
« Reply #13 on: Jul 11th, 2003, 12:13pm » |
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1. Many answers fit perfectly. In fact, many more than I thought!
2. A hint for the 'original' solution: some roman numerals look similar to decimal, while other don't.
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TenaliRaman
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Re: Matches time again
« Reply #14 on: Jul 14th, 2003, 4:40am » |
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This may not be the original intended answer.
||| - | = || |--|
111-1=110
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Self discovery comes when a man measures himself against an obstacle - Antoine de Saint Exupery
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BNC
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Re: Matches time again
« Reply #15 on: Jul 16th, 2003, 2:52am » |
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on Jul 14th, 2003, 4:40am, TenaliRaman wrote:This may not be the original intended answer.
<hidden> |
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Actually, yes, it is.
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TenaliRaman
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Re: Matches time again
« Reply #16 on: Jul 17th, 2003, 10:41am » |
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yeehaw!! 
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Self discovery comes when a man measures himself against an obstacle - Antoine de Saint Exupery
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