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   Author  Topic: Alphabet Categories  (Read 456 times)
otter
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Alphabet Categories  
« on: May 20th, 2003, 8:54pm »
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The letters of the english alphabet can be grouped into four distinct categories.  The first 13 letters establish the categories:

     A M
     B C D E K
     F G J L
     H I

Place the remaining 13 letters in their proper categories and explain your reasoning.
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Leo Broukhis
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Re: Alphabet Categories  
« Reply #1 on: May 20th, 2003, 10:31pm »
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No, there are 5 categories. The fifth category consists of three letters.
« Last Edit: May 20th, 2003, 10:32pm by Leo Broukhis » IP Logged
Chronos
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Re: Alphabet Categories  
« Reply #2 on: May 20th, 2003, 11:21pm »
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Leonid, I think that he's putting those in category 3 (with F, G, J, L, and P)
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redPEPPER
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Re: Alphabet Categories  
« Reply #3 on: May 21st, 2003, 2:28pm »
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NSZ
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Icarus
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Re: Alphabet Categories  
« Reply #4 on: May 21st, 2003, 3:30pm »
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I first saw this one (with the groups all completely specified - your job was only to explain them) in Marilyn Vos Savant's column. She too included NSZ in "group three". I was disappointed to read her explanation that this group consisted of letters "with no symmetry at all!". I agree with Leonid that these three belong in their own category.
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otter
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Re: Alphabet Categories  
« Reply #5 on: May 21st, 2003, 6:19pm »
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I guess I missed this in Marilyn vos Savant's column.  The version I remember had only 4 categories.  But the 4 or 5 categories argument nothwithstanding, I see you all have the answer.
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Re: Alphabet Categories  
« Reply #6 on: May 22nd, 2003, 3:30pm »
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It was a long time ago, and M.V.S. had only 4 categories too. That was the problem - In her answer to the question, she explained how the other 3 categories were vetically symmetric, horizontally symmetric, and both. Then she asked the readers to identify the property possessed by the fourth category. Her answer at the end of the column was that it consisted of letters with no symmetry at all. Even though it contained N, S, and Z, which are center symmetric. Hence my disappointment.
 
Actually the puzzle as you stated it has two solutions - in that you can define the 3rd group as "having neither horizontal or vertical symmetry", and the 4th group as "having both symmetries" - in which case NSZ is part of the third group. Or you could define the 3rd group as "not symmetric under rigid transformations" and the 4th group as "symmetric about their centers" - in which case NSZ is part of the 4th group.
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"Pi goes on and on and on ...
And e is just as cursed.
I wonder: Which is larger
When their digits are reversed? " - Anonymous
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