wu :: forums
« wu :: forums - Too many solutions? »

Welcome, Guest. Please Login or Register.
Nov 29th, 2024, 8:02pm

RIDDLES SITE WRITE MATH! Home Home Help Help Search Search Members Members Login Login Register Register
   wu :: forums
   riddles
   easy
(Moderators: Eigenray, towr, ThudnBlunder, william wu, SMQ, Grimbal, Icarus)
   Too many solutions?
« Previous topic | Next topic »
Pages: 1  Reply Reply Notify of replies Notify of replies Send Topic Send Topic Print Print
   Author  Topic: Too many solutions?  (Read 1831 times)
BNC
Uberpuzzler
*****





   


Gender: male
Posts: 1732
Too many solutions?  
« on: Jan 29th, 2003, 11:24am »
Quote Quote Modify Modify

A quadratic equation has either 2, 1 or 0 unique real solutions.
 
Well, look at this equation (nice work, towr!):
 

Assume a<b<c
 
BUT:
x=a; x=b and x=c are all uniqe solutions!
 
 
[edit]
Hi!
Can't seem to link to the formula (#28 on towr's database). Can anyone help?
[/edit]
 
 
« Last Edit: Jan 29th, 2003, 10:57pm by BNC » IP Logged

How about supercalifragilisticexpialidociouspuzzler [Towr, 2007]
towr
wu::riddles Moderator
Uberpuzzler
*****



Some people are average, some are just mean.

   


Gender: male
Posts: 13730
Re: Too many solutions?  
« Reply #1 on: Jan 29th, 2003, 12:58pm »
Quote Quote Modify Modify

You forgot a 'b' at the end of the url..
Maybe an easier alternative is to use formula?id=28
(Which makes you wonder why I didn't put that under image at the first place)
 
for the time being..:

 
[edit 25/2/03]the reason for using an md5 as index is when the database disappears and all formulas get renumbered (it's now 24)  
hmmzz.. For some strange reason using the md5 doesn't work for this formula when linked from anywhere on this board.. It works for other formulae, and from other places.. peculiar[/edit]
« Last Edit: Feb 25th, 2003, 2:48am by towr » IP Logged

Wikipedia, Google, Mathworld, Integer sequence DB
James Fingas
Uberpuzzler
*****





   
Email

Gender: male
Posts: 949
Re: Too many solutions?  
« Reply #2 on: Jan 29th, 2003, 1:24pm »
Quote Quote Modify Modify

BNC,
 
That is a very clever puzzle! It makes me wonder if there are even more solutions, other than x=a, x=b, x=c ... so much for the foundations of mathematics!
IP Logged

Doc, I'm addicted to advice! What should I do?
Icarus
wu::riddles Moderator
Uberpuzzler
*****



Boldly going where even angels fear to tread.

   


Gender: male
Posts: 4863
Re: Too many solutions?  
« Reply #3 on: Jan 29th, 2003, 7:08pm »
Quote Quote Modify Modify

Very clever indeed! But James, I don't follow your hidden remark. The "wonder" is true but what does this say about the foundations of mathematics? Or am I being dense?   Undecided
IP Logged

"Pi goes on and on and on ...
And e is just as cursed.
I wonder: Which is larger
When their digits are reversed? " - Anonymous
lukes new shoes
Newbie
*





   
Email

Gender: male
Posts: 34
Re: Too many solutions?  
« Reply #4 on: Jan 30th, 2003, 5:10am »
Quote Quote Modify Modify

the equation isnt actually a quadratic
IP Logged
aero guy
Guest

Email

Re: Too many solutions?  
« Reply #5 on: Jan 30th, 2003, 5:17am »
Quote Quote Modify Modify Remove Remove

Nice hint James.  I "figured it out" by noting that the equation is AT MOST quadratic.  I assume that if I bothered to reduce it you would get a nifty little answer.
IP Logged
Garzahd
Junior Member
**





    mlahut


Gender: male
Posts: 130
Re: Too many solutions?  
« Reply #6 on: Jan 30th, 2003, 10:38am »
Quote Quote Modify Modify

Sure enough. If you make a common denominator, you get
 
(x-a)(x-b)(a-b) + (x-b)(x-c)(b-c) - (x-a)(x-c)(a-c) = (a-b)(b-c)(a-c)
 
(this reduction becomes much simpler if you remember that (a-b) = -(b-a). )
 
Anyway, check the coefficients of x2 in the expansion of the left side: a-b + b-c - (a-c) = 0.
IP Logged
James Fingas
Uberpuzzler
*****





   
Email

Gender: male
Posts: 949
Re: Too many solutions?  
« Reply #7 on: Jan 30th, 2003, 11:16am »
Quote Quote Modify Modify

I wasn't going to hide my remark, but then I thought:
"What if somebody tries another value for x? Then for sure they will figure it out!"
IP Logged

Doc, I'm addicted to advice! What should I do?
aero_guy
Senior Riddler
****





   
Email

Gender: male
Posts: 513
Re: Too many solutions?  
« Reply #8 on: Jan 31st, 2003, 12:04pm »
Quote Quote Modify Modify

that is the nifty part of the problem: they make it very easy to try a, b, or c, but you get into a bunch of algebra with anything else.
IP Logged
cathy
Guest

Email

Re: Too many solutions?  
« Reply #9 on: Jul 14th, 2003, 3:33pm »
Quote Quote Modify Modify Remove Remove

If you expend the equation, you will realize that all the unknows cancel out. So, this are infinite number of solutions. not only does x=a, x=b, x=c satify this equation, x can be anything and still satify this equation.
 
A simply example so that you can understand this easier.
 
x+a = x +a
 
how do you solve this equation? you cancel out the x on both sides and realize that no matter what x is, the equation will always be satified. x = a, x = b, x = c..... does matter.
 
even though this is a first order equation, it still had infinite number of solutions.  
 
The same theory goes for the complicated equation in this question. It just takes a little more time to realize that you can cancel out all the x-terms.
IP Logged
Pages: 1  Reply Reply Notify of replies Notify of replies Send Topic Send Topic Print Print

« Previous topic | Next topic »

Powered by YaBB 1 Gold - SP 1.4!
Forum software copyright © 2000-2004 Yet another Bulletin Board