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Topic: How to divide with SIC sbn instruction (Read 7051 times) |
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MOR
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How to divide with SIC sbn instruction
« on: Mar 25th, 2013, 2:26am » |
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Hello there,
I want to implement the C code
Code:
on SIC with sbn instruction.
Any help with this?
The command does the following:
sbn a,b,c # Mem[a] = Mem[a] – Mem[b];if (Mem[a]<0) go to c
I am looking forward to hearing from you and i would appreciate any kind of help. thank you.
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akasina9
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x = 0x2B | ~ 0x2B. x is the question
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Re: How to divide with SIC sbn instruction
« Reply #1 on: Apr 2nd, 2013, 9:29pm » |
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You can look at division as a subtraction loop. The following code block assumes that the initial instruction starts at address n:
Code:sbn u, u # Initialize u to 0
sbn c, c # Initialize c to 0
sbn u, ONE # Initialize u to -1
sbn a, b, n+6 # Subtract b from a until it is less than zero
sbn c, u # increment c by one each time a is positive
sbn ZERO, ONE, n+3 # Unconditional jump to the subtraction step
exit
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