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   Minimum lines to cover
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   Author  Topic: Minimum lines to cover  (Read 5554 times)
bazinga
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Minimum lines to cover  
« on: Oct 15th, 2012, 10:06pm »
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Given a 2-d array of 1' and 0's , give an algorithm to find minimum number of horizontal/vertical lines to cover all the zeros.
 
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For each position of zero check whether the number of 0's are greater in row or col. If row has more 0's draw one horizontal line otherwise if col has more 0's draw a vertical line. If 0's are equal in all rows and columns then arbitrarily break the tie.
Is this correct?  
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towr
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Re: Minimum lines to cover  
« Reply #1 on: Oct 16th, 2012, 10:28am »
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It doesn't give the optimal solution for
0 0 0
1 1 0
1 0 1
0 1 1
Three vertical lines will cover all zeroes, but if you start with a horizontal line (covering the greatest numbers of zeroes to start with), you still need three additional lines.
 
To start with, I'd look at each row/column that has only one 0, and then draw a line perpendicular through it. Because you need a line through that 0 anyway, and you may cross off extra ones this way. So it's a no-lose step. That doesn't provide a complete solution though.
Perhaps it'd work if, when you get stuck, you make a greedy choice (a line through most uncovered zeroes).
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Aryabhatta
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Re: Minimum lines to cover  
« Reply #2 on: Oct 17th, 2012, 9:26am »
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This is the minimum vertex cover problem for bi-partite graphs and has known fast solutions.
 
See this lecture: http://lucatrevisan.wordpress.com/2011/02/23/cs261-lecture14-algorithms- in-bipartite-graphs/
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